The vertex form of the equation of a parabola is x=8(y-1)^2-15. What is the standard form of the equation?
thanx
To convert the equation from vertex form to standard form, we need to expand and simplify.
Given equation: x = 8(y - 1)^2 - 15
First, let's expand the square term:
x = 8(y^2 - 2y + 1) - 15
Next, distribute 8 to each term inside the parenthesis:
x = 8y^2 - 16y + 8 - 15
Combine like terms:
x = 8y^2 - 16y - 7
Therefore, the standard form of the equation is:
8y^2 - 16y - x - 7 = 0
To convert the given equation from vertex form to standard form, we need to expand and simplify it.
The vertex form of a parabola equation is given by x = a(y - k)^2 + h, where (h, k) represents the coordinates of the vertex.
In the given equation, the vertex is (h, k) = (0, 1), and we have x = 8(y - 1)^2 - 15.
To convert it to the standard form, we'll expand and simplify:
x = 8(y - 1)^2 - 15
x = 8(y^2 - 2y + 1) - 15
x = 8y^2 - 16y + 8 - 15
x = 8y^2 - 16y - 7
So, the standard form of the equation is x = 8y^2 - 16y - 7.
x = 8(y-1)^2-15
x = 8(y^2-2y+1)-15
x = 8y^2-16y-7