A car is travelling at a speed of 30.0m/s encounters an emergency and comes to a complete stop. How much time will it take for the car to stop at -4.0m/s^2
a = -4 m/s^2
v = -4t + k
when t = 0, v = 3-
thus k = 30
v = -4t + 30
when the vehicle stops, v = 0
0 = -4t + 30
4t = 30
t = 30/4 or 7.5 seconds
To determine how much time it will take for the car to stop, we can use the equation:
v = u + at
Where:
v = final velocity (0 m/s, since the car comes to a complete stop)
u = initial velocity (30.0 m/s)
a = acceleration (-4.0 m/s^2)
t = time
Rearranging the equation to solve for time (t):
t = (v - u) / a
Plugging in the values:
t = (0 - 30.0) / (-4.0)
Now we can calculate the time it will take for the car to stop.
To find the time it takes for the car to stop, we can use the equation of motion:
v = u + at
Where:
v = final velocity (0 m/s, since the car comes to a complete stop)
u = initial velocity (30.0 m/s)
a = acceleration (-4.0 m/s^2)
t = time
Rearranging the equation to solve for time (t), we get:
t = (v - u) / a
Plugging in the values:
t = (0 - 30.0) / -4.0
Simplifying:
t = 30.0 / 4.0
t = 7.5 seconds
So, it will take 7.5 seconds for the car to come to a complete stop at an acceleration of -4.0 m/s^2.