A fully opened parachute is shaped like a hemisphere and has a diameter of 8m.
Which of the following is closet to
the volume of air that can fit in the fully opened parachute
a)134m3
b)268m3
c)1072m3
d)2145m3
(1/2)(4/3)pi r^3
a little bigger than (2)(4^3)
2 * 64
128
a
To find the volume of air that can fit in the fully opened parachute, we can use the formula for the volume of a hemisphere, which is (2/3)πr^3, where r is the radius of the hemisphere.
Given that the diameter of the parachute is 8m, we can find the radius by dividing the diameter by 2:
r = 8m / 2 = 4m
Now, we can substitute this value into the formula for the volume of a hemisphere:
Volume = (2/3)π(4m)^3
Volume = (2/3)π(64m^3)
Volume = (128/3)πm^3
To evaluate the closest option, we need to approximate the value of π. Let's assume π is approximately 3.14:
Volume ≈ (128/3) * 3.14 * m^3
Volume ≈ 1341.59m^3 ≈ 1340m^3
Among the options given:
a) 134m3
b) 268m3
c) 1072m3
d) 2145m3
The closest answer to the volume of air that can fit in the fully opened parachute is option a) 134m3.