If you pick a gumball at random, put it back, and then pick another gumball at random, what is the probability of picking a blue gumball then picking a yellow gumball?
We have to know how many gumballs there are and how many of each colour.
this was a pretty crappy question
To find the probability of picking a blue gumball and then picking a yellow gumball, we need to consider two factors:
1. The probability of picking a blue gumball on the first draw.
2. The probability of picking a yellow gumball on the second draw, given that we picked a blue gumball on the first draw.
Let's assume that there are a total of n gumballs in the jar, with b blue gumballs and y yellow gumballs.
1. The probability of picking a blue gumball on the first draw is b/n. Since we put the gumball back after the first draw, the total number of gumballs remains the same for the second draw.
2. The probability of picking a yellow gumball on the second draw, given that we picked a blue gumball on the first draw, is y/n. This is because, after replacing the gumball, we still have y yellow gumballs and n total gumballs in the jar.
To find the probability of both events occurring, we multiply the probabilities together:
P(Blue and Yellow) = (b/n) * (y/n) = (b * y) / (n * n)
Therefore, the probability of picking a blue gumball and then picking a yellow gumball is (b * y) / (n * n).