Spring of 20cm extend to 30cm under a force of 10N.what will be its total length when extended by a force of 10N?

Umm. Didn't you just tell me 30cm

To find the total length of the spring when extended by a force of 10N, we need to understand Hooke's Law, which states that the extension of a spring is proportional to the force applied to it.

Hooke's Law can be represented by the equation:

F = kx

where:
F is the force applied to the spring,
k is the spring constant,
x is the extension of the spring.

To find the spring constant (k), we can rearrange the equation to solve for k:

k = F / x

Given that the spring extends from 20cm to 30cm under a force of 10N, the extension (x) is calculated as:

x = 30cm - 20cm = 10cm

Now we can find the value of the spring constant (k):

k = 10N / 10cm = 1 N/cm

To determine the total length of the spring when extended by a force of 10N, we can use the following equation:

F = kx

Substituting the given force and the calculated spring constant:

10N = (1 N/cm) * x

Solving for x:

x = 10N / (1 N/cm) = 10 cm

Therefore, the total length of the spring when extended by a force of 10N is 30cm (initial length) + 10cm (extension) = 40cm.