if the pressure on a 1.00 L sample of gas is increased from 760. mm Hg to 2.00 atm at constant temperature what will the volume of the gas sample
p1v1 = p2v2
To determine the final volume of the gas sample, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional at constant temperature.
Boyle's Law equation is:
P₁V₁ = P₂V₂
where:
P₁ = initial pressure (760. mm Hg)
V₁ = initial volume (1.00 L)
P₂ = final pressure (2.00 atm)
V₂ = final volume (unknown)
First, we need to convert the initial pressure from mm Hg to atm. Since 1 atm is equal to 760 mm Hg, we have:
P₁ = 760. mm Hg / 760 mm Hg/atm = 1.00 atm
Now we can rearrange the Boyle's Law equation to solve for V₂:
(V₁ * P₁) = (V₂ * P₂)
V₂ = (V₁ * P₁) / P₂
Substituting the given values:
V₂ = (1.00 L * 1.00 atm) / 2.00 atm
V₂ = 0.50 L
Therefore, the final volume of the gas sample is 0.50 L.