x2 - 4px +8

hey what do i do with typo i think

if it's derivative

take the 'p' as a constant
dy/dp=2x-4p

oops dx/dp not dy/dp

since there is no question, I see little point in hinting at answers.

To simplify the expression x^2 - 4px + 8, you can factor it if possible. However, it seems that this expression cannot be factored further, so we'll leave it in its current form.

If you were asked to solve the equation x^2 - 4px + 8 = 0, you could use the quadratic formula or complete the square to find the roots of the equation.

Using the quadratic formula, which states that for an equation in the form ax^2 + bx + c = 0, the roots are given by:

x = (-b ± √(b^2 - 4ac)) / (2a)

Comparing this with our equation x^2 - 4px + 8 = 0, we can identify the following values:

a = 1, b = -4p, c = 8

Plugging these values into the quadratic formula, we get:

x = (-(-4p) ± √((-4p)^2 - 4(1)(8))) / (2(1))
x = (4p ± √(16p^2 - 32)) / 2

Simplifying this further yields:

x = 2p ± √(4p^2 - 8)

So, the roots of the equation x^2 - 4px + 8 = 0 are x = 2p ± √(4p^2 - 8).