posted by Sam .
Consider the following reaction:
PbCl2 + 2 NaOH → Pb(OH)2 + 2 NaCl
What would be the major species observed floating in solution after one mole of PbCl2 and 2 moles of NaOH are mixed in aqueous
1. Na+ ions, Cl− ions and H+ ions
2. Pb2+ ions, Cl− ions, Na+ ions and OH− ions
3. Na+ and OH− ions
4. Pb2+ ions, Cl− ions and Na+ ions
5. Pb2+ ions, Na+ ions and OH− ions
6. Cl− ions and Na+ ions
7. Pb2+ ions, Cl− ions, Na+ ions, H+ ions and OH− ions
I don't get the point of this question.
a. The word "mixed" in water...LeadII chloride is very slightly soluble, only about 11 grams/liter, so how much water was there?
b. major species OBSERVED floating in solution...I have never seen, nor know anyone who have seen ions floating "in solution". That is ridiculous.
c. Now if you added the quanities you stated, in say a liter of water, then you would have left much leadII Chloride, and much unreacted sodium hydroxide, just a tad of insoluble LeadII hydroxide, and a few sodium ions, hydroxide ions, and chloride ions. But NO ONE would see these species floating in solution. Because of the very high pH, very few H+ ions would be there.
d. Somehow, I don't get the pont of this question at all. Or the author missed the boat on proofing it.
Ditto Bob Pursley and his comments.