David Wetterman drops a 5 kg watermelon from the top of a 30 m building. What is the velocity of the watermelon as it smashes into the ground (neglecting air resistance)?
24.25
24.25
vf^2=2*g*d
vf=sqrt(2*9.8*30)
To determine the velocity of the watermelon as it smashes into the ground, we can use the principles of physics, specifically the equation for calculating the final velocity of an object in free fall.
The equation for the final velocity of an object in free fall is:
v = √(2gh)
where v is the final velocity, g is the acceleration due to gravity (approximately 9.8 m/s²), and h is the height from which the object is dropped.
In this case, the height (h) is given as 30 meters. So, we can substitute the values into the equation:
v = √(2 * 9.8 m/s² * 30 m)
v = √(588 m²/s²)
v ≈ 24.25 m/s
Therefore, the velocity of the watermelon as it smashes into the ground (neglecting air resistance) is approximately 24.25 m/s.