A brick has mass 10kg and dimensions (10*5*20)cm
Find the maximum and minimum pressure it can exert on ground
area of big face = .1*.2 = .02 m^2
so min pressure = 10*9.81/.02 Pascals
and max = 10*9.81/(.1*.05)
Thank you sir.
You are welcome.
To find the maximum and minimum pressure that the brick can exert on the ground, we need to calculate the force and the area of contact between the brick and the ground.
First, let's calculate the force exerted by the brick on the ground. The force (F) can be calculated using Newton's Second Law, which states that force is equal to the mass (m) times the acceleration (a):
F = m * a
Since the brick is at rest on the ground, the acceleration (a) is equal to 0. Therefore, the force (F) will be 0 as well.
Next, let's calculate the area of contact between the brick and the ground. The area (A) can be calculated using the formula:
A = length * width
In this case, the length is 10 cm, the width is 5 cm, and the height is not relevant for calculating the area of contact. Therefore, the area of contact will be:
A = 10 cm * 5 cm = 50 cm²
Now, we can calculate the maximum and minimum pressure (P) exerted by the brick on the ground. Pressure is defined as the force per unit area, so:
P = F / A
Since the force (F) is 0, the maximum and minimum pressure will both be 0.
Therefore, the maximum and minimum pressure that the brick can exert on the ground is 0.