The drawing shows a jet engine suspended beneath the wing of an airplane. The weight W with arrow of the engine is 11900 N and acts as shown in the drawing. In flight the engine produces a thrust T with arrow of 64500 N that is parallel to the ground. The rotational axis in the drawing is perpendicular to the plane of the paper. With respect to this axis, find the magnitude of the torque due to each of the following forces.
Not having the drawing I can not do moment arms. You need the distances.
Your so silly
To find the magnitude of the torque due to each force, we need to calculate the moment arm of each force and then multiply it by the magnitude of the force.
1. The weight W:
The moment arm of the weight is the perpendicular distance from the rotational axis to the line of action of the force. Since the weight is acting vertically downward, the moment arm is equal to the horizontal distance between the axis and the line of action of the force.
To calculate the moment arm, we need to determine this horizontal distance in the given drawing.
2. The thrust T:
The thrust is acting parallel to the ground, which means it is acting horizontally. Since it is perpendicular to the rotational axis, the moment arm of the thrust is simply the distance from the rotational axis to the line of action of the force. Again, we need to determine this distance in the given drawing.
Once we have determined the moment arms for both forces, we can calculate the torque using the formula:
Torque = Force x Moment Arm
By substituting the magnitudes of the forces and their respective moment arms, we can find the torque due to each force.