A car starts to move nd accelerated at 4m/s2 for 8 seconds (u=0 V=32m/s a=4 m/s2 t=8) How fast is it moving? How far does it travel in this time?
Vf=a*t
distance=1/2 a t^2
A body covers distance of 80 meter in 7 second and 24 meter in 9th second how much shall it covers in 15 second?
To calculate how fast the car is moving, you can use the equation of motion:
v = u + at
Where:
v = final velocity
u = initial velocity
a = acceleration
t = time
In this case:
u = 0 m/s (since the initial velocity is given as 0)
a = 4 m/s^2
t = 8 seconds
Plugging in these values:
v = 0 + (4 × 8)
v = 0 + 32
v = 32 m/s
Therefore, the car is moving at a speed of 32 m/s.
To calculate the distance traveled by the car, you can use the equation of motion:
s = ut + (1/2)at^2
Where:
s = distance traveled
u = initial velocity
t = time
a = acceleration
In this case, we know:
u = 0 m/s (initial velocity)
a = 4 m/s^2 (acceleration)
t = 8 seconds (time)
Plugging in these values:
s = (0 × 8) + (1/2)(4 × (8^2))
s = 0 + (1/2)(4 × 64)
s = 0 + (1/2)(256)
s = 0 + 128
s = 128 meters
Therefore, the car travels a distance of 128 meters in this time.