For questions 1and 2, use integer values of x from -3 to 3 to graph the equation.
1. Y=-2x^2+3 (1 point)
so, plot a few points and draw the curve.
To graph the equation y = -2x^2 + 3, we will substitute several integer values of x into the equation to find the corresponding y-values.
Let's start by using integer values of x from -3 to 3:
For x = -3:
y = -2(-3)^2 + 3
= -2(9) + 3
= -18 + 3
= -15
So, for x = -3, y = -15.
For x = -2:
y = -2(-2)^2 + 3
= -2(4) + 3
= -8 + 3
= -5
So, for x = -2, y = -5.
For x = -1:
y = -2(-1)^2 + 3
= -2(1) + 3
= -2 + 3
= 1
So, for x = -1, y = 1.
For x = 0:
y = -2(0)^2 + 3
= -2(0) + 3
= 0 + 3
= 3
So, for x = 0, y = 3.
For x = 1:
y = -2(1)^2 + 3
= -2(1) + 3
= -2 + 3
= 1
So, for x = 1, y = 1.
For x = 2:
y = -2(2)^2 + 3
= -2(4) + 3
= -8 + 3
= -5
So, for x = 2, y = -5.
For x = 3:
y = -2(3)^2 + 3
= -2(9) + 3
= -18 + 3
= -15
So, for x = 3, y = -15.
Now that we have the corresponding values for x and y, we can plot them on a graph. By connecting the points, we can visualize the shape of the graph.