Mr. Fried plans to give fruit flies to 6 groups of lab students for an experiment. He wants to give the same number of flies to each group. He has different size bottles. How can Mr. Fried give each group the same number of fruit flies without opening the bottles?
2 large bottles: 12 fruit flies in each bottle
10 medium bottles: 8 fruit flies in each bottle
14 small bottles: 2 fruit flies in each bottle
To give each group the same number of fruit flies without opening the bottles, Mr. Fried can follow these steps:
1. Calculate the total number of fruit flies in each bottle size:
- Large bottles: 2 bottles x 12 flies/bottle = 24 flies
- Medium bottles: 10 bottles x 8 flies/bottle = 80 flies
- Small bottles: 14 bottles x 2 flies/bottle = 28 flies
2. Determine the desired number of fruit flies per group: Divide the total number of flies by the number of groups.
- Total fruit flies: 24 flies + 80 flies + 28 flies = 132 flies
- Number of groups: 6 groups
- Desired number of flies per group: 132 flies ÷ 6 groups = 22 flies
3. Distribute the fruit flies from each bottle size to each group by dividing the desired number of flies per group by the number of flies in each bottle size:
- Large bottles: 22 flies ÷ 12 flies/bottle = 1.8333 bottles (round up to 2 bottles)
- Medium bottles: 22 flies ÷ 8 flies/bottle = 2.75 bottles (round up to 3 bottles)
- Small bottles: 22 flies ÷ 2 flies/bottle = 11 bottles
4. Assign the corresponding number of bottles to each group:
- Large bottles: Give 2 bottles to each group, distributing the 12 flies in each bottle evenly.
- Medium bottles: Give 3 bottles to each group, distributing the 8 flies in each bottle evenly.
- Small bottles: Give 11 bottles to each group, distributing the 2 flies in each bottle evenly.
By following these steps, Mr. Fried can give each group the same number of fruit flies without opening the bottles.
To give each group the same number of fruit flies without opening the bottles, Mr. Fried needs to ensure that the number of fruit flies in each bottle is divisible by the number of groups he has, which is 6 in this case.
First, let's find the common divisor for all the bottle sizes. In this case, the common divisor for 12, 8, and 2 is 2.
Next, Mr. Fried needs to calculate how many bottles of each size to give to each group. Since he has 6 groups, he can distribute the bottles evenly among the groups.
For the large bottles, he has 2 bottles with 12 flies each. The common divisor is 2, so each bottle can be split into 6 groups with 6 flies each. Therefore, Mr. Fried can give each group one large bottle.
For the medium bottles, he has 10 bottles with 8 flies each. The common divisor is 2, so each bottle can be split into 4 groups with 2 flies each. Therefore, Mr. Fried can give each group two medium bottles.
For the small bottles, he has 14 bottles with 2 flies each. The common divisor is 2, so each bottle can be split into 1 group with 2 flies. Therefore, Mr. Fried can give each group 14 small bottles.
In summary, to give each group the same number of fruit flies without opening the bottles, Mr. Fried can give each group one large bottle, two medium bottles, and 14 small bottles.
He has 24+80+28 total flies, divided by six grups, is 132/6=22 flies each.
how can we get 22
1 large bottle, 1med, plus 1small (guve those to two groups)
Now we have four groups left, no large, 8 med, and 12 small left.
give 2 med, plus 3 small to 4 groups
he is now out of large, out of med, and no small left. Poor Mr Feied