A 1.00-kg beaker containing 2.29 kg of oil (density = 916 kg/m3) rests on a scale. A 2.33-kg block of iron is suspended from a spring scale and is completely submerged in the oil (see figure below). Find the equilibrium readings of both scales.

top scale
N

bottom scale
N

need density of iron

top scale has
2.33 - Viron*916
but Viron = 2.33/density of iron

To find the equilibrium readings of both scales, let's analyze the forces acting on the system.

1. The beaker containing the oil is resting on a scale. The weight of the beaker and the oil will be acting downwards. The equation to calculate the weight is:

Weight = mass * gravitational acceleration

Given that the mass of the beaker and oil is 1.00 kg + 2.29 kg = 3.29 kg, and the gravitational acceleration is approximately 9.8 m/s^2, we can calculate the weight:

Weight of beaker and oil = 3.29 kg * 9.8 m/s^2 = 32.142 N

So, the top scale reading will be 32.142 N.

2. The iron block is completely submerged in the oil. It will experience a buoyant force upwards and its weight downwards. The net force on the iron block will be zero for it to be in equilibrium.

The buoyant force is given by:

Buoyant force = Volume of the submerged block * Density of the fluid * Gravitational acceleration

The volume of the submerged block can be calculated using its density and mass:

Volume of block = Mass of block / Density of iron

Given that the mass of the block is 2.33 kg and the density of iron is approximately 7,860 kg/m^3, we can calculate the volume:

Volume of block = 2.33 kg / 7,860 kg/m^3 ≈ 0.000296 m^3

Now we can calculate the buoyant force:

Buoyant force = 0.000296 m^3 * 916 kg/m^3 * 9.8 m/s^2 ≈ 2.7 N

So, the net force acting on the iron block will be its weight minus the buoyant force:

Net force on the block = Weight of block - Buoyant force

Weight of block = mass * gravitational acceleration

Weight of block = 2.33 kg * 9.8 m/s^2 ≈ 22.834 N

Net force on the block = 22.834 N - 2.7 N ≈ 20.134 N

Hence, the bottom scale reading will be approximately 20.134 N.

Therefore, the equilibrium readings of the scales are:

Top scale: 32.142 N
Bottom scale: 20.134 N