A farmer has enough seeds to grow 200 crops of wheat and 300 crops of oats in one season. However, his water supply is limited to growing only 250 crops. Find a system of inequalities that describes the possibilities for his farming.
If there are x wheat and y oats,
x <= 200
y <= 300
x+y <= 250
To find the system of inequalities that describes the possibilities for the farmer's farming, we need to consider the limitations of both the seeds and the water supply.
Let's assume the number of crops of wheat the farmer grows is represented by the variable "x", and the number of crops of oats is represented by the variable "y". We can set up the following inequalities:
1. The number of crops of wheat cannot exceed 200:
x ≤ 200
2. The number of crops of oats cannot exceed 300:
y ≤ 300
3. The total number of crops grown (wheat + oats) cannot exceed the water supply of 250:
x + y ≤ 250
Thus, the system of inequalities that describes the possibilities for the farmer's farming is:
x ≤ 200
y ≤ 300
x + y ≤ 250