In the equation 2 NaN3----2 Na + 3 N2// how much N2 would be produced if 100 grams of NaN2 completely reacted at STP?
for each mole of NaN3 used, one gets 1.5 moles of N2.
so how many moles of NaN3 is 100grams?
150 moles
To determine the amount of N2 produced when 100 grams of NaN3 completely reacts at STP (Standard Temperature and Pressure), we need to follow these steps:
Step 1: Calculate the molar mass of NaN3.
We can determine the molar mass of NaN3 by adding up the atomic masses of sodium (Na) and nitrogen (N) in the formula:
Na: 23 grams/mol (atomic mass of sodium)
N: 14 grams/mol (atomic mass of nitrogen)
So, the molar mass of NaN3 is:
molar mass of NaN3 = (2 * atomic mass of Na) + (3 * atomic mass of N)
= (2 * 23 grams/mol) + (3 * 14 grams/mol)
= 46 grams/mol + 42 grams/mol
= 88 grams/mol
Step 2: Convert grams of NaN3 to moles.
To convert the given mass of NaN3 to moles, you can use the formula:
moles = mass / molar mass
moles of NaN3 = 100 grams / 88 grams/mol
≈ 1.136 moles
Step 3: Apply the stoichiometry of the balanced equation.
From the balanced equation:
2 NaN3 -----> 2 Na + 3 N2
We can see that for every 2 moles of NaN3, we get 3 moles of N2.
Step 4: Calculate the moles of N2 produced.
To determine the moles of N2 produced, we can use the molar ratio obtained from the balanced equation.
moles of N2 = moles of NaN3 * (3 moles of N2 / 2 moles of NaN3)
= 1.136 moles * (3/2)
≈ 1.704 moles
Step 5: Convert moles of N2 to grams.
The molar mass of N2 can be used to convert moles to grams:
molar mass of N2 = 28 grams/mol (atomic mass of nitrogen)
grams of N2 = moles of N2 * molar mass of N2
= 1.704 moles * 28 grams/mol
≈ 47.712 grams
Therefore, approximately 47.712 grams of N2 would be produced when 100 grams of NaN3 completely reacts at STP.
To determine how much N2 would be produced if 100 grams of NaN3 completely reacted at STP, we need to first calculate the molar mass of NaN3 and then use stoichiometry to convert grams of NaN3 to moles of NaN3 and then moles of N2.
Step 1: Calculate the molar mass of NaN3.
The molar mass of one sodium atom (Na) is approximately 22.99 g/mol.
The molar mass of one nitrogen atom (N) is approximately 14.01 g/mol.
To calculate the molar mass of NaN3, we add the atomic masses of each atom:
Sodium (Na): 22.99 g/mol
Nitrogen (N): 14.01 g/mol
Total molar mass: 22.99 g/mol + 3(14.01 g/mol) = 65.00 g/mol
Step 2: Convert grams of NaN3 to moles of NaN3.
Using the given mass of 100 grams and the molar mass of NaN3 (65.00 g/mol), we can set up the following conversion:
100 g NaN3 * (1 mol/65.00 g) = 1.54 mol NaN3
Step 3: Use stoichiometry to convert moles of NaN3 to moles of N2.
From the balanced equation, we can see that for every 2 moles of NaN3, we get 3 moles of N2.
Therefore, using the calculated moles of NaN3 (1.54 mol), we can set up the following ratio:
1.54 mol NaN3 * (3 mol N2/2 mol NaN3) = 2.31 mol N2
Thus, if 100 grams of NaN3 completely reacted at STP, it would produce approximately 2.31 moles of N2.