Let A(t) = 3- 2t^2 + 4^t. Find A(2) - A(1).

a(2)-a(1)=-2(2^2)+4^2+2(1^2)-4^1

= -8+16+2-4=6 check that.

A(t) = 3- 2t^2 + 4^t

A(2) - A(1)
= 3 - 2(4) + 4(4) - (3 - 2(1) + 4(1))
= 3 - 8 + 16 - 3 + 2 - 4
= 6

you are correct

To find A(2) - A(1), we first need to find the value of A(2) and A(1), and then subtract them.

Given the function A(t) = 3 - 2t^2 + 4^t, we substitute t = 2 and t = 1 into the function to find their respective values.

For A(2):
A(2) = 3 - 2(2)^2 + 4^2
= 3 - 2(4) + 16
= 3 - 8 + 16
= 19

For A(1):
A(1) = 3 - 2(1)^2 + 4^1
= 3 - 2(1) + 4
= 3 - 2 + 4
= 5

Now, we can calculate A(2) - A(1):

A(2) - A(1) = 19 - 5
= 14

Therefore, A(2) - A(1) equals 14.