Suppose a certain species of fawns between 1 and 5 months old have a body weight that is approximately

normally distributed with mean µ = 25 kilograms and standard deviation σ = 8 kilograms.
Let x be the weight of a fawn in kilograms.
Convert the following z interval to a x interval.

z > 3.3

Enter you answer as follows: x>#

To convert the given z interval to an x interval, we need to use the formula for converting z-scores to raw scores.

The formula is: x = µ + (z * σ)

Firstly, let's determine the value of x when z = 3.3:
x = 25 + (3.3 * 8)
x = 25 + 26.4
x = 51.4

Now, we need to convert the inequality "z > 3.3" to an inequality involving x. Since this is a greater than sign, we know that the corresponding x value will be greater than 51.4.

Therefore, the x interval for the given z interval is x > 51.4.