A and B are two alloys of gold and copper,prepared by mixing metals in the ratio 7:2 and 7:11 respectively.if equal quantity of alloys are melted to form a third alloy C.find the ratio of gold and C
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equal quanities?
then the final ratio is
14:13
To find the ratio of gold in alloy C, we need to calculate the amount of gold in alloys A and B.
Let's start with alloy A, which is prepared by mixing gold and copper in the ratio 7:2. So, if we assume the quantity of gold in alloy A is 7x and the quantity of copper is 2x, the total quantity of alloy A would be 7x + 2x = 9x.
Now, let's calculate the amount of gold in alloy B. Alloy B is prepared by mixing gold and copper in the ratio 7:11. So, if we assume the quantity of gold in alloy B is 7y and the quantity of copper is 11y, the total quantity of alloy B would be 7y + 11y = 18y.
Since we are melting equal quantities of alloys A and B to form alloy C, the total quantity of alloy C would be 9x + 18y.
To find the ratio of gold in alloy C, we need to compare the quantity of gold in alloy C to the total quantity of alloy C. Let's assume the quantity of gold in alloy C is z.
Therefore, the ratio of gold in alloy C would be z : (9x + 18y).
Please note that we would need additional information such as the values of x and y to calculate the exact ratio of gold in alloy C.