the volume of the shape below is placed into a bow that is 10 feet tall and the area of the base is 48ft squared feet. to the nearest tenth what is the remaining space.
The figure is a sphere that has a radius of 6 ft. r=6ft
I really need help figuring how to do this.
*box not bow srry
anyone there
as I read the problem, it is a box filled with a sphere, and you want to know the space outside the sphere.
if the crosssectional area of the box is 48ft^2, and the diameter of the sphere is 12, I don't see how a sphere of that diameter could fit in the box, so I am at a loss to understand the problem.
that's what the problem exactly said. maybe my teacher did a misprint
To find the remaining space in the bowl, you need to subtract the volume of the sphere from the volume of the bowl.
First, let's find the volume of the sphere using the formula:
Volume of a sphere = (4/3) * π * r^3
In this case, the radius (r) is given as 6 feet:
Volume of the sphere = (4/3) * π * (6^3)
Next, calculate the volume of the bowl as a cylinder. The formula for the volume of a cylinder is:
Volume of a cylinder = π * r^2 * h
Here, the radius (r) is also given as 6 feet, and the height (h) of the bowl is given as 10 feet:
Volume of the bowl = π * (6^2) * 10
Finally, subtract the volume of the sphere from the volume of the bowl to find the remaining space:
Remaining space = Volume of the bowl - Volume of the sphere
After performing the calculations, you can round the answer to the nearest tenth.
Let's go through the calculations step by step:
Calculating the volume of the sphere:
Volume of the sphere = (4/3) * 3.14 * (6^3)
Calculating the volume of the bowl:
Volume of the bowl = 3.14 * (6^2) * 10
Subtracting the volume of the sphere from the volume of the bowl to find the remaining space:
Remaining space = Volume of the bowl - Volume of the sphere
Finally, round the answer to the nearest tenth to get your result.