the weight of the block if wood is 96.5 N. the coefficient of static friction between the block of wood and vertical wall is 0.45. what minimum force is required to prevent the block from sliding down the wall
the weight of the block if wood is 96.5 N. the coefficient of static friction between the block of wood and vertical wall is 0.45. what minimum force is required to prevent the block from sliding down the wall.....
Why did the block of wood go to therapy? Because it had some serious friction issues with the wall! Now, let's calculate the minimum force required to prevent it from sliding down.
The minimum force required to prevent the block from sliding down the wall is equal to the force of static friction between the block and the wall. The formula for static friction is:
F_static = coefficient of static friction * normal force
Given that the weight of the block is 96.5 N, and the coefficient of static friction is 0.45, we can calculate the normal force as the weight of the block acting perpendicular to the wall:
Normal force = weight of the block = 96.5 N
Now, let's calculate the minimum force required:
F_static = 0.45 * 96.5 N = 43.425 N
So, the minimum force required to prevent the block from sliding down the wall is approximately 43.425 N.
To find the minimum force required to prevent the block from sliding down the wall, we need to consider the forces acting on the block.
1. Gravitational Force (Weight):
The weight of the block is given as 96.5 N. This force acts vertically downward.
2. Normal Force:
The block is pressed against the wall, so the wall exerts a force perpendicular to the surface of contact, known as the normal force.
3. Static Frictional Force:
The coefficient of static friction between the block and the vertical wall is given as 0.45. The static frictional force acts parallel to the surface of contact, opposing any tendency of motion.
To prevent the block from sliding down the wall, the force of static friction between the block and the wall must be equal to or greater than the force component due to the weight of the block acting perpendicular to the wall.
The equation for static friction is: fs ≤ μs * N,
where fs is the static frictional force, μs is the coefficient of static friction, and N is the normal force.
In this case, we need to find the minimum force, so we consider the maximum static frictional force. Therefore, the equation becomes: fs = μs * N.
The normal force is equal to the weight of the block due to there being no vertical acceleration. Thus, N = weight = 96.5 N.
Substituting the values into the equation, we have:
fs = μs * N
fs = 0.45 * 96.5
fs = 43.425 N.
Therefore, the minimum force required to prevent the block from sliding down the wall is 43.425 N.