Hi guys, Im doing algebraic fractions and I got this fraction:

(x^2+2x+1)/(x^2+1) ,
but the answers say that this is correct:
(x^2-1)/(x^2-2x-1).

So is (x^2+2x+1)/(x^2+1) = (x^2-1)/(x^2-2x-1)?

Thanks in advance

see

(x^2+2x+1)/(x^2+1)
((x^2+x)+(x+1)]/(x^2+1)
x(x+1)+1(x+1)/(x^2+1)
(x+1)^2/(x^2+1)....What i see

Hard to tell without the original question.

As collins pointed out, your answer and the apparent correct answer do not match.

State the original question and how you got your answer.

To determine if the two expressions are equal, we need to simplify both fractions and compare the results.

Let's start by simplifying the first fraction, (x^2 + 2x + 1) / (x^2 + 1):

1. Factor the numerator:
The numerator, x^2 + 2x + 1, can be factored as (x + 1)(x + 1) or (x + 1)^2.

2. Factor the denominator:
The denominator, x^2 + 1, cannot be factored any further since it is a sum of two squares.

So, after factoring the numerator and leaving the denominator unfactored, we have:
(x^2 + 2x + 1) / (x^2 + 1) = (x + 1)^2 / (x^2 + 1)

Now let's simplify the second fraction, (x^2 - 1) / (x^2 - 2x - 1):

1. Factor the numerator:
The numerator, x^2 - 1, is a difference of squares and can be factored as (x + 1)(x - 1).

2. Factor the denominator:
The denominator, x^2 - 2x - 1, cannot be factored any further.

So, after factoring both the numerator and denominator, we have:
(x^2 - 1) / (x^2 - 2x - 1) = (x + 1)(x - 1) / (x^2 - 2x - 1)

By comparing both simplified expressions, we can see that they are different:
(x + 1)^2 / (x^2 + 1) ≠ (x + 1)(x - 1) / (x^2 - 2x - 1)

Therefore, (x^2 + 2x + 1) / (x^2 + 1) is not equal to (x^2 - 1) / (x^2 - 2x - 1).

If the answers are suggesting otherwise, there might be an error in the solutions provided.