You have 1.0 liter of .45 M HCLO (aq). At 25 degrees Celsius, Ka= 3.5x10^8 for this acid. Calculate the pH of .45 M HCLO and the concentration of CLO- at equilibrium.

Thank you very much for any amount of help you are willing to give me.

I think you have made a typo. That surely is a Ka of 3.5E-8.

........HClO ==> H^+ + ClO^-
I......0.45M.....0......0
C......-x........x......x
E.....0.45-x.....x......x

Substitute the E line into the Ka expression and solve for x = (H^+) = (ClO^-)
Convert H^+ to pH