If 210 mL of isopropyl alcohol is diluted with water to a total volume of 300 mL, what is the percent by volume of isopropyl alcohol in the solution?

Would it be 70%??

you are diluting it 210/300 times, so new percent is 100 x dilution factor, or 70 percent.

To find the percent by volume of isopropyl alcohol in the solution, you need to know the volume of isopropyl alcohol and the total volume of the solution.

Given that you have initially 210 mL of isopropyl alcohol, and the final volume of the solution is 300 mL, you can find the percent by volume of isopropyl alcohol as follows:

Step 1: Determine the volume of water in the solution.
Since the volume of the solution is 300 mL and the volume of the isopropyl alcohol is 210 mL, the volume of water in the solution can be calculated as:
Volume of water = Total volume of solution - Volume of isopropyl alcohol
Volume of water = 300 mL - 210 mL
Volume of water = 90 mL

Step 2: Calculate the percentage of isopropyl alcohol.
The percentage of isopropyl alcohol can be calculated using the following formula:
Percentage of isopropyl alcohol = (Volume of isopropyl alcohol / Total volume of solution) * 100

Substituting the known values:
Percentage of isopropyl alcohol = (210 mL / 300 mL) * 100
Percentage of isopropyl alcohol = 0.7 * 100
Percentage of isopropyl alcohol = 70%

Therefore, the correct answer is 70%.