How do I work this problem?
m=-3, (4,5)
I gues you are looking for a straight line of slope m = 3 through the point (4,5)
y = 3 x + b
5 = 3*4 + b
5 = 12 + b
b = -7
so
y = 3 x - 7
or, since you have a point and a slope, you can just use the point-slope form:
y-5 = 3(x-4)
To work with this problem, you need to find the equation of a line using the slope-intercept form, which is:
y = mx + b
Here, "m" is the slope of the line, and "b" is the y-intercept.
Given that m = -3, you can substitute this value into the equation:
y = -3x + b
To find the value of "b," you will need to use the coordinates (4,5) of a point on the line. Substitute the values of x and y into the equation, and solve for "b":
5 = -3(4) + b
5 = -12 + b
b = 5 + 12
b = 17
Now that you have found the value of "b," you can write the final equation for the line:
y = -3x + 17
So, the equation of the line with slope m = -3 passing through the point (4,5) is y = -3x + 17.