10.5g of zinc trioxocarbonate(iv) were heated very stronglu to a constant mass and the residue treated with excess Hcl.calculate the mass of zinc chloride
Please give me the answer ido not know
show working step by step please
How did you get 136 and 0.1
i want to learn
ZnCO3+2HCl ==> ZnCl2+ H2O+CO2
1 mole of ZnCO3=1 mole of ZnCl2
1 mole =10.5/125
Therefore, 10.5/125 *136
Mole=mass/molar mass
Mass = molar mass * mole
i.e. m =136 * 0.1
m = 13.6g
ZnCO3 ==> ZnO + CO2
ZnO + 2HCl ==> ZnCl2 + H2O
mols ZnCO3 = grams/molar mass = ?
1 mol ZnCO3 gives 1 mol ZnO
1 mol ZnO produces 1 mol ZnCl2.
grams ZnCl2 = mols ZnCl2 x molar mass ZnCl3.