You and your friend are selling tickets to a charity event. You sell 7 adult tickets and 16 student tickets for $120. Your friend sells 13 adult tickets and 9 student tickets for $140. What is the cost of a student ticket?
Adult: $X each.
Student: $Y each.
Eq1: 7x + 16y = 120.
Eq2: 13x + 9y = 140.
Multiply Eq1 by 13, Eq2 by 7, and subtract:
91x + 208y = 1560
91x + 63y = 980
Diff.:145y = 580.
Y = $4.00.
you and your friend are selling tickets to a charity event. you sell 9 adult and 13 student tickets for 212 dollars. your friend sells 4 adult and 15 student tickets for 168 dollars. what was the cost of a student ticket.
Well, selling tickets with your friend! How exciting! Let's solve this mystery, shall we?
Let's start by figuring out the cost of adult tickets. You sold 7 adult tickets, and your friend sold 13. Both of you earned a total of $120 and $140, respectively. So, we can set up an equation:
7a + 13a = 120 + 140
Now, let's move on to the student tickets. You sold 16 student tickets, and your friend sold 9. Using the same equation theory:
16s + 9s = 120 + 140
Oh boy, this is getting intense. We need to solve these equations. By combining like terms:
20a = 260
25s = 260
Dividing by 20 and 25:
a = 13
s = 10.4
Hmm, well, we can't really have a fraction of a student ticket, can we? That would make hunger a part of the event, and nobody wants a hangry crowd at a charity event. So, let's use our skills of approximation and round 10.4 to 10.
Therefore, the cost of a student ticket would be approximately $10.
But remember, this answer is for humorous purposes only, so please consult actual math to obtain a precise solution.
To find the cost of a student ticket, we can set up a system of equations based on the given information. Let's denote the cost of an adult ticket as 'a' and the cost of a student ticket as 's'.
From the information given, we can write two equations:
Equation 1: 7a + 16s = 120 (based on the tickets you sold)
Equation 2: 13a + 9s = 140 (based on the tickets your friend sold)
To solve this system of equations, we can use the method of substitution or elimination. Let's solve it using the method of substitution:
From Equation 1, we can rearrange it to express a in terms of s:
7a = 120 - 16s
a = (120 - 16s)/7
Now substitute this value of a in Equation 2:
13((120 - 16s)/7) + 9s = 140
Simplify and solve for s:
(1560 - 208s)/7 + 9s = 140
Multiply through by 7:
1560 - 208s + 63s = 980
-145s = -580
s = (-580)/(-145)
s = 4
Therefore, the cost of a student ticket is $4.