Mrs Lopez has $9,118 in her bank account on March 1 she saves $609 in March. Then, she must pay $1,011 in taxes in April. Mrs Lopez is able to save $705 in May. At the end of May approoimately how much greater or less is her account balance than it was on March 17 Select each contect choice. A. her account balance is apparently $300 greater B. Her account balance is approximately $l,100 greater, C Her account balance is approximately $2.300 less D. Her account balance is apprormately S9400. E. Her account balance is approximately $9 200

Question

Mrs Lopez has $9,118 in her bank account on March 1 she saves $609 in March. Then, she must pay $1,011 in taxes in April. Mrs Lopez is able to save $705 in May. At the end of May approoimately how much greater or less is her account balance than it was on March 17 Select each contect choice. A. her account balance is apparently $300 greater B. Her account balance is approximately $l,100 greater, C Her account balance is approximately $2.300 less D. Her account balance is apprormately S9400. E. Her account balance is approximately $9 200

Answer 1

D is the best choice.

Answer 2

A is the best choice

Answer 3

The Ans. is A because I made test for my students and when I scanned it the correct ans. was A so bobpusley you are wrong.

Answer 4

To solve this problem, we need to keep track of Mrs. Lopez's account balance and calculate any changes made to it.

Step 1: Mrs. Lopez's account balance on March 1 is $9,118.

Step 2: In March, she saves $609, so her account balance at the end of March is: 9,118 + 609 = $9,727.

Step 3: Mrs. Lopez then pays $1,011 in taxes in April, so her account balance at the end of April is: 9,727 - 1,011 = $8,716.

Step 4: In May, she saves $705, so her account balance at the end of May is: 8,716 + 705 = $9,421.

Step 5: Now, we need to compare her account balance on May 31 to her account balance on March 17. To do that, we need to determine her account balance on March 17.

Step 6: Assuming that her account balance grows linearly, we can calculate the daily increase in her account balance by dividing the total increase from March 1 to May 31 ($9,421 - $9,118 = $303) by the number of days in this period (31 + 30 + 31 = 92). The daily increase is approximately $3.293.

Step 7: To find her account balance on March 17, we need to determine the number of days between March 1 and March 17 (17). Multiplying this by the daily increase gives us: $3.293 * 17 = $55.951.

Step 8: Adding the calculated increase to Mrs. Lopez's account balance on March 1, we get her account balance on March 17: $9,118 + $55.951 = $9,173.951.

Step 9: Now we compare her account balance on May 31 ($9,421) to her account balance on March 17 ($9,173.951).

The difference between these two values is: $9,421 - $9,173.951 = $247.049.

So, the correct answer is:

A. Her account balance is approximately $300 greater (since $247.049 is close to $300).