A pan filled with hot food cools from 94°C to 86°C in 2minutes when the room temperaturs is at 20°C .How long will it take to cool from 71°C to 69°C ?

No response

0.7min or 42secs

42secs

To determine how long it will take for the pan to cool from 71°C to 69°C, we first need to find out the rate at which the temperature is decreasing.

In this case, we know that the temperature of the pan decreased by 12°C (from 94°C to 86°C) in 2 minutes. Therefore, we can calculate the rate of temperature decrease as follows:

Rate of temperature decrease = (Temperature difference) / (Time difference)
Rate of temperature decrease = (94°C - 86°C) / 2 minutes
Rate of temperature decrease = 8°C / 2 minutes
Rate of temperature decrease = 4°C/minute

Now that we know the rate of temperature decrease is 4°C/minute, we can calculate the time it will take for the pan to cool from 71°C to 69°C:

Time = (Temperature difference) / (Rate of temperature decrease)
Time = (71°C - 69°C) / 4°C/minute
Time = 2°C / 4°C/minute
Time = 0.5 minutes

Therefore, it will take 0.5 minutes for the pan to cool from 71°C to 69°C.