the age of jane and john add up to 25years.8years ago jane was twice as old as john.how old are they now?
Oh, I see, it is math, well check physics below.
Let
x be Jane's age now
y be John's age now
They have said
x+y = 25
(x-8) = 2(y-8)
So, just solve for x and y.
To solve this problem, let's assign variables to represent the ages of Jane and John.
Let's say Jane's age is J, and John's age is J.
According to the information given:
1) The age of Jane and John add up to 25 years, so J + J = 25.
2) Eight years ago, Jane was twice as old as John, so J - 8 = 2(J - 8).
To solve this system of equations, let's start with equation 1:
J + J = 25
2J = 25
J = 25/2
J = 12.5
Now let's substitute J = 12.5 into equation 2:
J - 8 = 2(J - 8)
12.5 - 8 = 2(12.5 - 8)
4.5 = 2(4.5)
4.5 = 9
However, this is not a valid solution because Jane's age, J, cannot be 12.5.
Therefore, there seems to be an error or inconsistency in the problem, and we cannot determine the ages of Jane and John with the given information.
Please double-check the information provided or provide additional details if available.