# calculas

posted by Sagar

consider the following.
Function
y = cos 3x
point (pi/4, -square root of 2/2)

(a) Find an equation of the tangent line to the graph of f at the given point. (Let x be the independent variable and y be the dependent variable.)

1. Steve

first, find the slope of the tangent line anywhere:

y' = -3sin(3x)
so, at x=π/4, y = -3sin(3π/4) = -3/√2

Now you have a point and a slope, so the line is

y + 1/√2 = -3/√2 (x - π/4)

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