Explain using the dilution formula how to prepare 0.2M HCL acid from 37% HCL acid
How to prepare 0.2m hcl solution
To prepare a 0.2M HCl acid solution from a 37% HCl acid solution, you can use the dilution formula. The dilution formula is given as:
C1V1 = C2V2
Where:
C1 = initial concentration of the solution
V1 = initial volume of the solution
C2 = final concentration of the solution
V2 = final volume of the solution
In this case, we want to prepare a 0.2M HCl acid solution, so C2 = 0.2 M.
Given that the 37% HCl acid solution is the initial solution, C1 = 37%.
Let's assume we want to prepare a total volume of 500 mL (V2 = 500 mL).
Now, let's rearrange the formula to solve for V1:
V1 = (C2 * V2) / C1
V1 = (0.2 M * 500 mL) / 0.37
V1 = 270.27 mL (approximately)
Therefore, to prepare a 0.2M HCl acid solution, you will need to take approximately 270.27 mL of the 37% HCl acid solution and then dilute it with distilled water to reach a final volume of 500 mL.
To prepare a 0.2M HCl acid solution from a 37% HCl acid solution, you can use the dilution formula. The dilution formula is:
C1 * V1 = C2 * V2
Where:
C1 is the initial concentration of the solution (37%)
V1 is the initial volume of the solution (unknown)
C2 is the final concentration of the solution (0.2M)
V2 is the final volume of the solution (desired volume)
To solve for the unknown value of V1, you need to rearrange the formula:
V1 = (C2 * V2) / C1
Now, let's plug in the known values:
C1 = 37%
C2 = 0.2M
V2 = desired volume (let's say 1 liter)
V1 = (0.2M * 1L) / 37%
Now, you need to convert the percentage concentration to a decimal form by dividing it by 100:
37% / 100 = 0.37
V1 = (0.2M * 1L) / 0.37
Simplifying the equation, we get:
V1 = 0.54 L
So, to prepare a 0.2M HCl acid solution from a 37% HCl acid solution, you would need to dilute 0.54 liters of the 37% HCl acid solution with water or another solvent to make a total volume of 1 liter.
I looked up the density of a 37% solution at 20 degrees C = 1.18
Then 1000 x 1.18 x 0.37 x (1/36.45) = 12.3 M for the HCl.
Then mL1 x M1 = Ml2 x M2
mL1 x 12.3 = 1000 mL x 0.2 assuming you want to prepare 1000 mL of the solution. So you take mL1 you calculate, add to a 1000 mL volumetric flask, and add DI water to the mark of the volumetric flask. Mix thoroughly.