Jason remembers nine digits of a ten digit phone number. He remembers that the last digit is an even number. If he guesses that last digit, what is the probability that he dials the correct number?

My answer: 1/5 probability

why 1/5? 5 of the 10 digits are even.

how do I do it then?

fyi this is actually right

Assuming 0 counts as an even digit, then the last digit must be 2, 4, 6, 8, 0 = 5 options
Only one of these is the correct one
Therefore the probability that he dials correctly = 1/5 or 0.20 or 20%

My bad. You are correct.

To determine the probability that Jason guesses the correct last digit of the phone number, we need to consider the possibilities.

Since Jason remembers nine digits of a ten-digit phone number, there are 10 possible digits for the last digit of the number (0-9).

Out of these 10 possible digits, there are 5 even digits (0, 2, 4, 6, 8). Therefore, the probability that Jason dials the correct number by guessing the last digit is 1 out of 5.

So, your answer of 1/5 probability is correct.