The solubility of sodium chloride is 35.9/100 ml in STP, try dissolving 1 kg of salt in 1 l of water what happens? how much salt will be dissolved and how much salt will be insoluble?
35.9 g NaCl x (1000 mL/100 mL) = 359 g NaCl that will dissolve in 1 L of H2O. Anything over that will not dissolve and the solution will be saturated. How much is left? That's 1000 g NaCl - 359 g NaCl = ?
thanks DrBob222 =)
To determine what happens when attempting to dissolve 1 kg of salt in 1 L of water, we need to compare the solubility of sodium chloride with the amount of salt we are trying to dissolve.
The given solubility of sodium chloride is 35.9 g/100 ml of water at standard temperature and pressure (STP). To convert 1 L of water to ml, we multiply by 1000, which gives us 1000 ml of water.
Now, we can calculate the maximum amount of sodium chloride that would dissolve in 1000 ml (1 L) of water, based on the given solubility:
35.9 g/100 ml × 1000 ml = 35,900 g (or 35.9 kg)
According to the solubility information, only 35.9 kg of sodium chloride can dissolve in 1 L of water at STP.
However, we are attempting to dissolve 1 kg of salt (sodium chloride). This amount exceeds the maximum solubility, so not all of the salt will dissolve. Since the solubility limit has been reached at 35.9 kg, any additional salt added will exceed the limit and remain insoluble.
Therefore, when attempting to dissolve 1 kg of salt in 1 L of water at STP, only 35.9 kg of salt will dissolve, while the remaining amount (1 kg - 35.9 kg) will be insoluble.