Solve using substitution
5x-2y= 0 and 3x=y =-1
I assume you meant 3x+y = -1
So, 6x+2y = -2
But, 2y=5x, so
6x+5x = -2
now solve for x and then get y.
You're right it should of read 3x=y=-1. Y is equal to -5/11. Please give a step by step to get -5/11 answer.i'm stuck on the fraction part.Thank you.
it's just a fraction.
x = -2/11
y = -5/11
That is the solution.
Fractions are numbers, just like 5 and -12. No reason to be afraid of them.
and that's
should have read 3x+y=-1
To solve this system of equations using substitution, we'll rearrange one of the equations to solve for one variable in terms of the other. Then we substitute this expression into the other equation and solve for the remaining variable.
Let's start with the second equation:
3x = y - 1
To isolate y, we add 1 to both sides:
y = 3x + 1
Now that we have y in terms of x, we can substitute this expression into the first equation:
5x - 2(3x + 1) = 0
Simplifying the equation gives us:
5x - 6x - 2 = 0
-x - 2 = 0
To solve for x, we isolate x by adding 2 to both sides:
-x = 2
Multiplying both sides by -1 to get x alone, we have:
x = -2
Now that we have the value of x, we can substitute it back into one of the original equations to solve for y. Let's use the second equation:
3x = y - 1
Substituting x = -2:
3(-2) = y - 1
-6 = y - 1
Now, solve for y by adding 1 to both sides:
-6 + 1 = y
-5 = y
Therefore, the solution to the system of equations is x = -2 and y = -5.