Algebra 2
posted by Bryan
Q: What is the value of b in the equation 4^2b3 = 8^1b?
My Work/Answer:
Set each sides base to 2
2^2(2b3) = 2^3(1b)
cancelled bases out
solved for b
my answer  9/7
Is my work and answer correct
Thank You

Reiny
Make sure you include brackets in your solution, at first look your equation made little sense.
4^(2b3) = 8^(1b)
(2^2)^(2b3) = (2^3)^(1b)
= 2^(4b6) = 2^(33b)
thus
4b6 = 33b
7b = 9
b = 9/7
how did you get 9/7 ?? 
Bryan
i got 9/7 the  was just to signify what it was sorry about the confusion. I should have put an equals sign
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