# Algebra 2

posted by Bryan

Q: What is the value of b in the equation 4^2b-3 = 8^1-b?

Set each sides base to 2
2^2(2b-3) = 2^3(1-b)
cancelled bases out
solved for b

Is my work and answer correct

Thank You

1. Reiny

4^(2b-3) = 8^(1-b)
(2^2)^(2b-3) = (2^3)^(1-b)
= 2^(4b-6) = 2^(3-3b)
thus
4b-6 = 3-3b
7b = 9
b = 9/7

how did you get -9/7 ??

2. Bryan

i got 9/7 the - was just to signify what it was sorry about the confusion. I should have put an equals sign

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