What is the average useful power output of a person who does 5.90×106 J of useful work in 7.90 h?
307 W
7.90h * 3600s/h = 28,440 s. = 2.84*10^4 s.
P = 5.90*10^6/2.84*10^4 = 207.5 J/s. = 207.5 Watts.
To find the average useful power output, we need to divide the useful work done by the time taken.
Useful power output (P) is given by the formula: P = W / t,
where P is the power in watts, W is the work done in joules (J), and t is the time taken in seconds (s).
Given that the useful work done (W) is 5.90×10^6 J and the time taken (t) is 7.90 hours, we need to convert the time into seconds since the unit of power is watts.
To convert hours to seconds, we use the conversion factor: 1 hour = 3600 seconds.
So, the time taken in seconds (t) is: 7.90 hours × 3600 seconds/hour = 28,440 seconds.
Now, we can substitute the values into the formula to find the average useful power output:
P = 5.90×10^6 J / 28,440 s.
Evaluating this expression will give us the average useful power output.