Jerry started doing sit-ups every day. The first day he did 19 sit-ups. Every day after that he did 2 more sit-ups than he had done the previous day. Today Jerry did 41 sit-ups. Write an equation that could be solved to find the number of days Jerry has been doing sit-ups, not counting the first day. Let n represent the number of days.
Jerry has been doing these push-ups for quite some time, as you can see in the Related Questions below.
Only the numbers keep changing.
Change the solution here to fit your problem
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To write the equation, we can use the information given. We know that Jerry did 19 sit-ups on the first day and every day after that he did 2 more sit-ups than the previous day. Let's break it down step by step.
Let's assume that the number of days Jerry has been doing sit-ups is represented by n (excluding the first day).
On the first day, he did 19 sit-ups.
The next day, he did 19 + 2 sit-ups.
The day after that, he did 19 + 2 + 2 sit-ups.
And so on.
In general, the number of sit-ups Jerry did on the nth day (excluding the first day) can be represented as 19 + 2 + 2 + ... (n times).
So, the equation can be written as:
19 + 2 + 2 + ... (n times) = 41
To simplify the equation, notice that the common difference between each day's sit-ups is 2. So, we can rewrite the equation as:
19 + 2n = 41
Therefore, the equation that could be solved to find the number of days Jerry has been doing sit-ups is:
19 + 2n = 41