The specific heat of aluminum is 0.900*j/g*C
How much heat is required to raise the temperature of a 30.0 g block of aluminum from to 25.0 oC to 75 oC?
mass*specificheat*changeinTemp
30*.9*50 joules
To calculate the amount of heat required to raise the temperature of a substance, we can use the formula:
Q = m * c * ΔT
Where:
Q is the heat required
m is the mass of the substance
c is the specific heat of the substance
ΔT is the change in temperature
Given:
m = 30.0 g (mass of aluminum block)
c = 0.900 J/g°C (specific heat of aluminum)
ΔT = 75°C - 25.0°C = 50.0°C (change in temperature)
Now, we can substitute the values into the formula to calculate the heat required:
Q = 30.0 g * 0.900 J/g°C * 50.0°C
Q = 1,350 J
Therefore, the amount of heat required to raise the temperature of a 30.0 g block of aluminum from 25.0°C to 75.0°C is 1,350 Joules.
To calculate the amount of heat required to raise the temperature of a substance, we can use the formula:
Q = m * c * ΔT
where:
Q is the amount of heat energy (in joules),
m is the mass of the substance (in grams),
c is the specific heat capacity of the substance (in joules/gram*°C), and
ΔT is the change in temperature (in °C).
In this case, we are given:
m = 30.0 g (mass of the aluminum block)
c = 0.900 J/g*°C (specific heat of aluminum)
ΔT = 75 °C - 25 °C = 50 °C (change in temperature)
Plugging in these values into the formula, we can calculate Q:
Q = 30.0 g * 0.900 J/g*°C * 50 °C
Q = 1350 J/g*°C * 50 °C
Q = 67500 J (joules)
Therefore, the amount of heat required to raise the temperature of a 30.0 g block of aluminum from 25.0 °C to 75.0 °C is 67500 joules.