Abel, Belle, And Cindy have $408 altogether. Belle has $7 more than Cindy and $5 more than Abel. How much does Abel have?

a+b+c = 408

b = c+7
b = a+5

now crank it out.

a + b + c = 408

b = c + 7 so c = b-7
b = a + 5

a + (a+5) + (a+5-7) = 408

3 a + 3 = 408

a + 1 = 136

a = 135

Let's assign variables to represent the unknowns:

Let "A" be Abel's amount of money.
Since Belle has $5 more than Abel, let "B" represent Belle's amount of money, which is A+5.
Since Belle has $7 more than Cindy, let "C" represent Cindy's amount of money, which is B-7.

We know that Abel, Belle, and Cindy have $408 altogether, so we can create an equation based on that:
A + B + C = 408

Substituting the values for B and C:
A + (A+5) + ((A+5)-7) = 408

Simplifying the equation:
A + A + 5 + A + 5 - 7 = 408
3A + 3 = 408
3A = 405
A = 135

Therefore, Abel has $135.

To find out how much Abel has, we need to set up an equation based on the information given. Let's suppose Abel has x dollars.

Since Belle has $5 more than Abel, we can say that Belle has x + $5.
Similarly, since Belle has $7 more than Cindy, we can say that Cindy has x - $7.

The total amount of money they have together is $408, so we can write the equation as:
x + (x + $5) + (x - $7) = $408.

Now, we can solve the equation to find the value of x:

x + x + $5 + x - $7 = $408
3x - $2 = $408
3x = $410
x = $410 / 3
x ≈ $136.67

Therefore, Abel has approximately $136.67.