The sum of the angle measures of a polygon w/ "s" sides is 2880. Find "s"

Please help with step-by-step explanation, so I can fully understand it. Thank you.

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No explanation needed, if you recall that the sum of the interior angles of a polygon with s sides is 180(s-2). So,

180(s-2) = 2880

I am searching for these number of sides of each regular polygon s whose total angle is 2880° and the calculation.

To find the number of sides "s" of a polygon given the sum of its angle measures, you can use the formula:

Sum of angle measures = (s - 2) * 180°

In this case, the sum of the angle measures is 2880°. Therefore, we can set up the equation:

2880 = (s - 2) * 180°

To solve for "s", let's isolate the variable by dividing both sides of the equation by 180°:

2880 / 180 = s - 2

Simplifying the left side of the equation:

16 = s - 2

Now, let's solve for "s" by adding 2 to both sides of the equation:

16 + 2 = s

Finally, simplifying the right side of the equation:

s = 18

So, the polygon has 18 sides.