A 1L flask contains 0.2moles of air open to atmosphere at 0degree celcius. Upon heating some of the air is lost. What is the percentage of air remaining in the flask?
To find the percentage of air remaining in the flask, we need to know the number of moles of air remaining. To do this, we can use the ideal gas law equation:
PV = nRT
Where:
P = pressure (in this case, atmospheric pressure)
V = volume (1L)
n = number of moles of air (initially 0.2 moles)
R = ideal gas constant
T = temperature (0 degree Celsius, which needs to be converted to Kelvin by adding 273.15)
First, let's find the pressure (P). Atmospheric pressure typically varies but is approximately 1 atmosphere (atm).
So, we have:
P = 1 atm
Next, let's convert the temperature (T) from Celsius to Kelvin:
T = 0 + 273.15 = 273.15 K
Now, we can rearrange the ideal gas law equation to solve for n (number of moles of air):
n = PV / RT
Substituting the known values:
n = (1 atm) * (1 L) / ((0.0821 L * atm / (mol * K)) * (273.15 K))
n = 0.0404 moles
So, after heating, there are 0.0404 moles of air remaining in the flask.
To find the percentage of air remaining, we can use the following formula:
Percentage remaining = (moles of air remaining / initial moles of air) * 100
Percentage remaining = (0.0404 moles / 0.2 moles) * 100
Percentage remaining = 20.2%
Therefore, the percentage of air remaining in the flask is approximately 20.2%.