Tim walks 7 miles east and then 6 miles north. How far is Tim from his starting point? Round your answer to the nearest whole number if necessary.
And your answer is?
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Would it be about 9 miles.
a^2+B=c^2
49+36 = c^2
85 = c^2 <-- do the square root
About 9 miles because 9^2 = 81 and it is closer.
Yes, about 9 miles
To find the distance Tim is from his starting point, we can use the Pythagorean theorem since Tim's path forms a right triangle. The two legs of the triangle represent the distances Tim walked east and north, and the hypotenuse represents the straight-line distance from his starting point.
Let's call the distance Tim walked east as leg A, which is 7 miles, and the distance Tim walked north as leg B, which is 6 miles.
To find the straight-line distance from his starting point (hypotenuse), we can use the Pythagorean theorem formula:
c^2 = a^2 + b^2,
where c is the hypotenuse, and a and b are the legs.
Applying this formula, we have:
c^2 = 7^2 + 6^2
= 49 + 36
= 85.
To find c, we need to take the square root of 85:
c = √(85).
Calculating this using a calculator or estimation, √85 is approximately 9.22.
Therefore, Tim is approximately 9.22 miles away from his starting point.