a 45-kg box initially at rest is being pushed with a force of 950 N along a frictionless horizontal surface. What is the speed of the boz after traveling a distance of 2.0m
F=ma
a=F/m
vf^2=2*a*d solve for Vf
To determine the speed of the box after traveling a distance of 2.0m, we can use the laws of motion.
First, we need to determine the acceleration of the box. We can use Newton's Second Law of Motion, which states that force is equal to mass multiplied by acceleration:
Force = mass × acceleration
Since the box is on a frictionless surface, the only force acting on it is the force being applied. Therefore, we can rewrite the equation as:
950 N = 45 kg × acceleration
Now, we can solve for the acceleration:
acceleration = 950 N / 45 kg
acceleration ≈ 21.11 m/s²
Next, we can use the kinematic equation to find the final speed of the box. The kinematic equation is:
v² = u² + 2as
Where:
v = final velocity (unknown)
u = initial velocity (in this case, the box is initially at rest, so u = 0)
a = acceleration (21.11 m/s²)
s = distance traveled (2.0m)
Plugging in the values:
v² = 0² + 2 × 21.11 m/s² × 2.0m
v² = 2 × 21.11 m/s² × 2.0m
v² = 84.44 m²/s²
v ≈ √84.44 m/s
v ≈ 9.19 m/s
Therefore, the speed of the box after traveling a distance of 2.0m is approximately 9.19 m/s.