6. Given the equation below, how many moles of each reactant were there if 13.7 moles of N2(g) is produced?
4NH3(g) + 6NO(g)→5N2(g) + 6H2O(g)
To solve this question
To determine the number of moles of each reactant, we can use the coefficients in the balanced chemical equation.
From the given balanced equation:
4NH3(g) + 6NO(g) → 5N2(g) + 6H2O(g)
We can see that the ratio of NH3 to N2 is 4:5.
Given that 13.7 moles of N2(g) is produced, we can set up a proportion using the ratio of coefficients:
4 moles of NH3 corresponds to 5 moles of N2
x moles of NH3 corresponds to 13.7 moles of N2
Using this proportion, we can solve for x (the number of moles of NH3):
(4 moles of NH3 / 5 moles of N2) = (x moles of NH3 / 13.7 moles of N2)
Cross-multiplying:
4 * 13.7 = 5 * x
54.8 = 5x
Dividing both sides by 5:
54.8 / 5 = x
x ≈ 10.96
Therefore, there were approximately 10.96 moles of NH3.
To find the number of moles of NO, we can use the same approach:
6 moles of NO corresponds to 5 moles of N2
y moles of NO corresponds to 13.7 moles of N2
Using the proportion:
(6 moles of NO / 5 moles of N2) = (y moles of NO / 13.7 moles of N2)
Cross-multiplying:
6 * 13.7 = 5 * y
82.2 = 5y
Dividing both sides by 5:
82.2 / 5 = y
y ≈ 16.44
Therefore, there were approximately 16.44 moles of NO.
To find the number of moles of each reactant, you need to use the stoichiometry of the balanced equation. The stoichiometry tells you the relative ratio between the reactants and products.
From the balanced equation:
4NH3(g) + 6NO(g) -> 5N2(g) + 6H2O(g)
The coefficient of NH3 is 4, and the coefficient of N2 is 5. This means that for every 4 moles of NH3, 5 moles of N2 are produced.
Since we know that 13.7 moles of N2(g) is produced, we can set up a ratio to find the moles of NH3:
(13.7 moles N2) x (4 moles NH3 / 5 moles N2) = 10.96 moles NH3
Therefore, there were approximately 10.96 moles of NH3 present.
Similarly, we can find the moles of NO by setting up a ratio:
(13.7 moles N2) x (6 moles NO / 5 moles N2) = 16.44 moles NO
Therefore, there were approximately 16.44 moles of NO present.
So, the number of moles of each reactant were approximately 10.96 moles of NH3 and 16.44 moles of NO.
Use the coefficients to tell you.
13.7 mols N2 x (4 mols NH3/5 mols N2) = ? mols NH3
13.7 mols N2 x (6 mols NO/5 mols N2) = ? mols NO