Find the change in the force of gravity between two planets when the distance between them is decreased by a factor of 4.7
The mass of a certain neutron star is 3.4e+30 kg(around 1.5 solar masses) and its radius is 8400 m. What is the acceleration of gravity at the surface of this condensed, burned-out star? (Note on scientific notation: 3e+30 means 310^30.)
1) F = Gm1m2/r^2 since the only thing changing is r, F increases by (1/4.7)^2
2) g = GM/r^2
To find the change in the force of gravity between two planets when the distance between them is decreased by a factor of 4.7, we can use the inverse square law for gravity.
The force of gravity between two objects is given by the equation:
F = G * (m1 * m2) / r^2
Where:
F is the force of gravity
G is the gravitational constant (approximately 6.67430 x 10^-11 N m^2 / kg^2)
m1 and m2 are the masses of the two planets
r is the distance between the centers of the two planets
When the distance between the two planets is decreased by a factor of 4.7, it means the new distance (r') is equal to the original distance (r) divided by 4.7.
So, we substitute the new distance (r') into the equation and compare it with the original distance (r) to find the change in the force of gravity.
Let's assume the original force of gravity is F1 and the new force of gravity is F2.
F1 = G * (m1 * m2) / r^2
F2 = G * (m1 * m2) / (r/4.7)^2
To find the change in force, we can subtract F2 from F1:
Change in force = F2 - F1
Now, input the values for the masses of the two planets, the original distance between them (r), and the gravitational constant (G) into the equations to calculate the original force of gravity (F1) and the new force of gravity (F2). Finally, subtract F2 from F1 to find the change in force.