A 100.00 ml of volume of 0.500 M HCl was mixed with 100.00 ml of 0.500 M KOH in a constant pressure calorimeter. The initial temperature of individual acid and base was 23.0 degree celsius. The final temperature after mixing was 25.5 degree celsius Given the specific heat of the solution was 3.97 J. g-1. Deg.-1
-1996
To determine the heat of reaction (or the enthalpy change, ΔH) for the neutralization reaction between HCl and KOH, you can use the equation:
q = m * c * ΔT
where:
q = heat absorbed or released by the reaction (in joules)
m = mass of the solution (in grams)
c = specific heat of the solution (in J/g·°C)
ΔT = change in temperature (in °C)
In this case, you have 100.00 mL of HCl and 100.00 mL of KOH, both with a concentration of 0.500 M. However, you need to convert the volumes to masses using the densities and molar masses of the solutions.
1. Calculate the mass of the HCl solution:
Volume of HCl = 100.00 mL = 0.10000 L
Density of HCl (assumed) = 1.00 g/mL
Mass of HCl = Volume of HCl * Density of HCl
2. Calculate the mass of the KOH solution:
Volume of KOH = 100.00 mL = 0.10000 L
Density of KOH (assumed) = 1.00 g/mL
Mass of KOH = Volume of KOH * Density of KOH
3. Calculate the total mass of the solution:
Total mass of solution = Mass of HCl + Mass of KOH
4. Determine the heat change using q = m * c * ΔT:
q = Total mass of solution * specific heat of the solution * ΔT
Plug in the values from the given information:
Total mass of solution = (Mass of HCl + Mass of KOH)
Specific heat of the solution = 3.97 J/g·°C
ΔT = (Final temperature - Initial temperature)
Substitute the values into the equation and calculate q to find the heat change (ΔH) for the neutralization reaction.