If D=7i-3j+2k. Find the magnitude of D
C'mon. Pythagorean twice.
Pls how to solve it
To find the magnitude of a vector, you need to use the formula:
|D| = sqrt(dx^2 + dy^2 + dz^2)
Where dx, dy, and dz are the components of the vector D.
In this case, D = 7i - 3j + 2k, so:
dx = 7
dy = -3
dz = 2
Substituting these values into the formula, we get:
|D| = sqrt((7)^2 + (-3)^2 + (2)^2)
= sqrt(49 + 9 + 4)
= sqrt(62)
Therefore, the magnitude of D is sqrt(62).