If D=7i-3j+2k. Find the magnitude of D

C'mon. Pythagorean twice.

Pls how to solve it

To find the magnitude of a vector, you need to use the formula:

|D| = sqrt(dx^2 + dy^2 + dz^2)

Where dx, dy, and dz are the components of the vector D.

In this case, D = 7i - 3j + 2k, so:

dx = 7
dy = -3
dz = 2

Substituting these values into the formula, we get:

|D| = sqrt((7)^2 + (-3)^2 + (2)^2)
= sqrt(49 + 9 + 4)
= sqrt(62)

Therefore, the magnitude of D is sqrt(62).