Concentrated hydrochloric acid is 12 M. What is the molarity of an HCl solution prepared by diluting 10.0mL of concentrated acid to a total volume of 250.0mL?
mL1 x M1 = mL2 x M2
10 x 12 = 250 x M2.
Solve for M2.
.48
To find the molarity of the diluted HCl solution, we can use the formula:
M₁V₁ = M₂V₂
where:
M₁ is the concentration of the concentrated HCl solution (12 M)
V₁ is the volume of the concentrated HCl solution used (10.0 mL)
M₂ is the molarity of the diluted HCl solution (unknown)
V₂ is the total volume of the diluted HCl solution (250.0 mL)
Let's plug in the values into the formula:
(12 M) x (10.0 mL) = M₂ x (250.0 mL)
120.0 = M₂ x 250.0
Now, solve for M₂ by dividing both sides of the equation by 250.0:
M₂ = 120.0 / 250.0
M₂ = 0.48 M
Therefore, the molarity of the HCl solution prepared by diluting 10.0 mL of concentrated acid to a total volume of 250.0 mL is 0.48 M.
To determine the molarity of the diluted HCl solution, we can use the formula:
M1 * V1 = M2 * V2
Where:
M1 = initial molarity of the concentrated acid
V1 = initial volume of the concentrated acid
M2 = final molarity of the diluted acid
V2 = final volume of the diluted acid
Given:
M1 (concentrated acid) = 12 M
V1 (concentrated acid) = 10.0 mL = 0.010 L
V2 (diluted acid) = 250.0 mL = 0.250 L
Let's substitute the values into the formula and solve for M2:
(12 M) * (0.010 L) = M2 * (0.250 L)
(12 / 0.250) = M2
48 M = M2
Therefore, the molarity of the HCl solution prepared by diluting 10.0 mL of concentrated acid to a total volume of 250.0 mL is 48 M.